Variations in the resistivity of blood can give valuable clues to changes in the blood's viscosity and other properties. the resistivity is measured by applying a small potential difference and measuring the current. suppose a medical device attaches electrodes into a 1.5-mm-diameter vein at two points 5.0 {\rm cm} apart. what is the blood resistivity if a 8.9 v potential difference causes a 240 \mu a current through the blood in the vein (in omega*m)?

The resistivity is 1.31 Ωm

Explanation:

Diameter = 1.5 mm

Potential difference = 8.9 V

Current = 240 μA

length = 5.0 cm

We need to calculate the resistivity

Using ohm's law

We know that,

Formula of resistance

Put the value of R in ohm's law

Where, = resistivity

A = area

I = length

Put the value into the formula

Hence, The resistivity is 1.31 Ωm

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s

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