The aluminum wire in a high-voltage transmission line is 2.7 cm in diameter. it is designed to carry a current of 1100 a. what is the voltage drop across a 32-km-long segment of this power line?

1660 V

Explanation:

Resistance should be determined and then voltage drop across the power line can be determined.

R = ρ L /A  

Here ρ = Resistivity of aluminum =

L = length = 32 km = 32,000 m

Area of cross section = A = π r² = π (0.027/2)² = 0.00057255 m²

Resistance = R =

( (32,000)/(0.00057255) = 1.5090 Ohms.

Voltage drop = V = I R = (1100)(1.5090) = 1659.9 V.

(If resistivity value is different, then the resistance will be different and hence final answer for voltage will also vary ).

i wanna say it’s between b and d, leaning more towards b.

dopamine..

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