The eyepiece of a compound microscope has a focal length of 2.5 cm and the objective lens has a focal length of 0.60 cm. the two lenses are separated by 14 cm. what is the overall magnification of the microscope?

191.67

Explanation:

focal length of objective lens, fo = 0.6 cm

focal length of eyepiece, fe = 2.5 cm

Distance between the lenses, L = 14 cm

Least distance of distinct vision for normal eye, d = 25 cm

The formula for the magnification of the compound microscope is given by

M = - 191.67

Thus, the magnification of the compound microscope is 191.67.

total distance/total time

(85 + 82)/(5+3)

167/8

20 just over

i think its d if wrong im sorry