If the diameter of a hole is 4.500 mm, what should be the diameter of a rivet at 23.0 ∘c, if its diameter is to equal that of the hole when the rivet is cooled to - 78.0 ∘c, the temperature of dry ice? assume that the expansion coefficient of aluminum is 2.4×10−5(∘c)−1 and remains constant.

Explanation:

diameter at 23 degree celcius is 4.511 mm

GIVEN DATA:

diameter of hole  = 4.500 mm

T_1 = 23.0 Degree celcius

T_2 = - 78.0 Degree celcius

expansion coeffcient of Al = 2.4*10^{-5} (degree celcius)^{-1}

diameter at 23 degree celcius is given as

   = 4.511 mm

diameter of rivet after change in temperature is given as

= 0.4511 cm

less than one you can't create energy

friction

explanation:

they us to move forward and backwards