Anon-standard issue u. s. federal reserve gold bar measures 7.00 x 4.625 x 2.14 inches. if gold has a density of 19.3 g/cm3 , what is the mass of a gold bar in kg and pounds?

mass is 48.1666 pound

Explanation:

given data

gold bar length L = 7 inches = 17.78 cm

gold bar width W = 4.625 inches = 11.75 cm

gold bar height H = 2.14 inches = 5.43 cm

gold density = 19.3 g/cm³

to find out

mass of gold bar

solution

we know volume of gold bar that is

volume = L×W×H    1

volume = 17.78×11.75×5.43

volume V = 1134.40 cm

now we know that

density = mass / volume    2

so put here value

19.3 = mass / 1134.40

mass = 19.3 × 1134.40

mass = 21893.92 gram

we know 1 gram = 0.0022 pound

so mass is 48.1666 pound

the old price per ounce is c/4.

the new price per ounce is c/3.6.

the ratio of the old price to the new one is

(c/4)/(c/3.6) = (c/c)×(3.6/4) = 0.9 . . = 9/10 . . "nine tenths" in either form