What is the relation between the wavelength, λ, and the momentum, p, of a particle? roughly what kinetic energy should an electron have in order for its wavelength be of roughly an "atomic" distance scale? re-express this as the number of volts needed to accelerate that electron from rest to this energy. would you call this a high-voltage device?

λ = h/p

This energy is equivalent to E=150.44eV

Explanation:

de Broglie Equation:

λ = h/p

h=6.63×10-34 m2 kg / s        Planck's constant

so: p=h/λ

On the other hand, an atomic distance, an angstrom, is equal:, λ should be similar to this distance.

Kinetics Energy of a electron, m=9.11×10−31 kg

Number of volts needed to accelerate that electron from rest to this energy:

So, this energy is equivalent to E=150.44eV

This high-voltage device is called: particles accelerator

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