Aperson is pushed up a ramp inclined upward at an angle θ above the horizontal as he sits in his desk chair that slides on frictionless rollers. the combined mass of the person and chair is m. he is pushed a distance x along the incline by a group of students who together exert a constant horizontal force of fa. the person’s speed at the bottom of the ramp is v0 m/s. use the work-energy theorem to find his speed at the top of the ramp.

Hi!

The work W done by force FA is W = FA*cos(θ)

The work-energy theorem say that the work W done by nonconservative forces is equal to the variation of mechanical energy:

If the distance moved is x, then the vertical displacement is x*sin(θ) Then,

We can solve for the speed v at the top of the ramp:

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.