Astudent holds a diverging lens 25.0 cm from the lettering on a poster on the wall. a virtual image of the letters is formed 10.5 cm between the lens and the wall. what are the focal length of the lens and orientation of the image? a) 7.4 cm and upright b) 7.4 cm and inverted c) 18.1 em and upright d) 18.1 em and inverted e) -7.4 cm and upright

-18.1 cm and upright

Explanation:

u = Object distance =  25 cm

v = Image distance = -10.5 cm

f = Focal length

Lens Equation

Focal length of the lens is -18.1 cm

Magnification

Since magnification is positive the image upright

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.

2b2t

explanation:

2b2t