While standing at the edge of a cliff, you throw a stone upward with an initial speed of 6.79 m/s. the stone subsequently falls to the ground, which 12.1 m below the point where the stone leaves your hand. at what speed does the stone impact the ground? ignore air resistance and take g= 9.81 m/s^2 a) 13.6 m/s
b) 14.5 m/s
c) 15.3 m/s
d) 16.8 m/s

d) 16.8 m/s

Explanation:

In this situation we are dealing with paarabolic motion with a constant acceleration (acceleration due gravity), hence, the following equation will be useful to find the

Where:

Is the final velocity of the stone

Is the initial velocity of the stone

is the constant acceleration of the stone due gravity

is the height of the cliff

This is the final velocity of the stone

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