Two cars are driving toward each other on a straight, flat kansas road. the jeep wrangler is traveling at 74.00 km/h north and the ford taurus is traveling at 49.00 km/h south, both measured relative to the road. what is the velocity of the jeep relative to an observer in the ford?

123 km/h

Explanation:

The distance between the Jeep Wrangler and the Ford Taurus is increasing.

Let us consider the north direction as positive when observing from the ground

So, the south direction will be negative

But when the observer is one of the cars the direction will be the same i.e., moving away from each other, so the velocity will be added.

Hence velocity of the Jeep relative to the Ford will be

Velocity of the Jeep + Velocity of the Ford

= 74+49 = 123 km/h

∴ Velocity of the Jeep relative to an observer in the Ford is 123 km/h

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz