13.an airplane starts from rest at the end of a runway and accelerates at a constant rate. in the first second, the airplane travels 1.11 m. how much additional distance will the airplane travel during the second second of its motion?

The answer is 3.33m

Explanation:

The acceleration "a" is constant.

Acceleration is the variation of velocity over time,

.

solving the last equation

,

where because the airplane starts from rest.

Once again, velocity is the variation of distance over time.

then

where if we consider  the end of the runway as the initial point (this step is for simplicity but you can let it expressed, it's going to cancel anyway).

If at , then

and the final expression for the distance is

.

If t = 2s, x = 4.44 m. Which means thad the additional distance is

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explanation: