At a given point in its orbit, the moon is 2.4 x 10^5 miles from earth. how long does it take light from a source on earth to reach a reflector on the moon and then return to earth? (speed of light is 3.0 x 10^8 m/s)

Total time= 2.56 s

Explanation:

Given that

So distance = 386242560 m

Velocity of light

We know that

Distance = velocity x time

Now by putting then values

t=1.28 s

So the total time = 2 x 1.28

total time= 2.56 s

Explanation:

Given that,

Distance between moon and earth,

1 mile = 1609.34 meters

Speed of light,

We need to find the time taken by the light from a source on earth to reach a reflector on the moon and then return to earth. Time is given by :

t = 1.28 seconds

Hence, this is the required solution.

thermal energy is the answer

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft