An object is placed 11.0 cm in front of a concave mirror whose focal length is 24.0 cm. the object is 2.60 cm tall. what is the height of the image? (cm)

Height of the image is 4.79 cm.

Explanation:

Object distance, u = -11 cm

Focal length of the mirror, f = -24 cm

Height of the object, h = 2.6 cm

We need to find the height of the image. Firstly, using the mirror's formula as :

v is the image distance

v = 20.30 cm

The magnification of the image is given by :

, h' is the height of the image

h' = 4.79 cm

So, the height of the image is 4.79 cm. Hence, this is the required solution.

"i have always loved contemporary art and made it a general goal to work within the field. after a few nonprofit internships at museums and galleries, i decided to try the for-profit art world and was offered a job as the ad assistant at the magazine. i much prefer the pace of the for-profit art community and have stayed with the company for three years, with a promotion to an account manager last spring."

i just did this and got a 100.

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2