How much energy is required to increase the temperature of 36.0 g of h2o from –20 °c to 50 °c, keeping in mind the following: vice ≈ 2.00 j/g×c liquid water ≈ 4.00 j/g×c δhfusion ≈ 6000 j/mol

2.06 x 10⁴ J

Explanation:

The process takes place in three steps. First, the ice is heated from -20 °C to 0 °C. Then the ice undergoes a phase change to water. Finally, the water is heated from 0 °C to 50 °C.

The heat energy required for the first step is as follows:

Q = mcΔT = (36.0 g)(2.00 Jg⁻¹°C⁻¹)(0 °C - (-20 °C)) = 1440 J

The heat energy required for the phase change (where L is the heat of fusion) is then calculated. Grams are converted to moles using the molar weight of water (18.02 g/mol)

Q = ML = (36.0 g)(mol/18.02g)(6000 J/mol) = 11987 J

Finally, the heat energy required to raise the temperature of the water to 50°C is calculated:

Q = mcΔT = (36.0 g)(4.00 Jg⁻¹°C⁻¹)(50 °C - 0 °C) = 7200 J

Adding all of the heat energy values together gives:

(1440 + 11987 + 7200) J = 20627 J

The final answer is 2.06 x 10⁴ J

muscle endurance

explanation:

i can do 50 in a row ( but i get so tired after that)

force is based upon mass and acceleration.the statement is not always true.

it can be explained from newton's second law of motion.

as per newton's second law of motion the rate of change of momentum is directly proportional to the applied force and takes place along the direction of force.

mathematically it can be written as -

                                              ⇒      

here   k is the proportionality constant whose value is 1.

                                                            [a is the acceleration=dv/dt]

hence we see that force not only depends on mass and acceleration but also on velocity and rate of change of mass. force f will depend on mass and acceleration only when mass is constant.

hence the statement that force is based upon mass and acceleration is false.