Acharge of -3.35 nc is placed at the origin of an xy-coordinate system, and a charge of 2.45 nc is placed on the y axis at y = 3.85 cm . part a if a third charge, of 5.00 nc , is now placed at the point x = 2.80 cm , y = 3.85 cm find the x and y components of the total force exerted on this charge by the other two charges.

Explanation:

We first have to get the distance and the angle between the points and the new charge.

to obtain the distance we have to do this:

the distance from charge of -3.35nC

and the angle:

θ

the distance from charge of -2.45nC

and the angle:

θ

Now we have to calculate the force applying coulomb:

The X component is equal to the magnitud of the force times Cos(θ):

because the charges are opposites the resultant force is negative

So the net force in X is:

The Y component is equal to the magnitud of the force times Sin(θ):

because the charges are opposites the resultant force is negative

So the net force on Y is:

its a 5.5 n

glad that

+15-35=-20

going in opposite directions