Three charged particles are placed at each of three corners of an equilateral triangle whose sides are of length 3.3 cm . two of the particles have a negative charge: q1 = -8.2 nc and q2 = -16.4 nc . the remaining particle has a positive charge, q3 = 8.0 nc . what is the net electric force acting on particle 3 due to particle 1 and particle 2?

N

Explanation:

We are given that three charged particle are placed at each corner  of equilateral triangle.

Side of equilateral triangle =3.3 cm=

We know that each angle of equilateral angle=

Net force=F =

Where k=

If we bisect the angle at then we have 30 degrees from there to either charge.

Direction of vertical force  due to charge and

Therefore, force will be added

Vertical  force=

Vertical net force=

Vertical  force =

Vertical  force= (towards

Horizontal component are opposite in direction then will b subtracted

Horizontal force=

Horizontal force= N(towards

Net electric force acting on particle 3 due to particle =

Net force=

Net force= N

car a and b are moving in opposite directions

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