Apellet gun is fired straight downward from the edge of a cliff that is 12.7 m above the ground. the pellet strikes the ground with a speed of 27.9 m/s. how far above the cliff edge would the pellet have gone had the gun been fired straight upward?

h₂ = 27.22m : height the pellet reaches

Explanation:

Pellet kinetics

Pellet moves with uniformly accelerated movement in  

freefall  

v f₁²=v₀²+2g*h₁ (formula 1)  : ball movement down

v f₂²=v₀²-2g*h₂ (formula (formula 2)  : ball movement up

d:displacement in meters (m)  

v₀: initial speed in m/s  

vf: final speed in m/s  

g: acceleration due to gravity in m/s²

h :height in m

Known data  

g=9.8 m/s²

h₁=12.7m

v f₁= 27.9 m/s

Initial velocity calculation (v₀)

We replace the data in formula 1:

27.9²=v₀²+2*9.8* 12.7

27.9²-2*9.8* 12.7=v₀²

529.49=v₀²

Calculation of the height that the pellet reaches when it goes up

Data:

v f₂=0 :When the pellet reaches the maximum height the final speed is zero

We replace the data in formula (2)

0²=23.1²-2*9.8*h₂

19.6h₂ =23.1²

h₂ =23.1²÷19.6

h₂ =27.22m

he made 11 calls in one day

electromagnetic shielding is the practice of reducing the electromagnetic field in a space by blocking the field with barriers made of conductive or magnetic materials. shielding is typically applied to enclosures to isolate electrical devices from their surroundings, and to cables to isolate wires from the environment through which the cable runs. electromagnetic shielding that blocks radio frequency electromagnetic radiation is also known as rf shielding.

the shielding can reduce the coupling of radio waves, electromagnetic fields and electrostatic fields. a conductive enclosure used to block electrostatic fields is also known as a faraday cage. the amount of reduction depends very much upon the material used, its thickness, the size of the shielded volume and the frequency of the fields of interest and the size, shape and orientation of apertures in a shield to an incident electromagnetic

from wikipedia