A+71 nc charge is positioned 1.9 m from a +42 nc charge. what is the magnitude of the electric field at the midpoint of these charges, in units of n/c?

The net Electric field at the mid point is 289.19 N/C

Given:

Q = + 71 nC =

Q' = + 42 nC =

Separation distance, d = 1.9 m

Solution:

To find the magnitude of electric field at the mid point,

Electric field at the mid-point due to charge Q is given by:

Now,

Electric field at the mid-point due to charge Q' is given by:

Now,

The net Electric field is given by:

c) up is the direction the magnetic force is acting on the charge.