An ice skater rotating about a vertical axis increases her angular velocity at constant rate from 7.85 rad/s to 10.65 rad/s in 2.3 s, thus her angular acceleration is 1.23 rad/s^2. during her rotation, her right leg outstretched horizontally. calculate the radial and tangential accelerations of her skate at the end of 2.3 s. her leg length is 90 cm.

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W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j