Acertain freely falling object, released from rest, requires 1.95 s to travel the last 23.5 m before it hits the ground. (a) find the velocity of the object when it is 23.5 m above the ground. (indicate the direction with the sign of your answer. let the positive direction be upward.) m/s (b) find the total distance the object travels during the fall. m

(a). The velocity of the object is -2.496 m/s.

(b).  The total distance of the object travels during the fall is 23.80 m.

Explanation:

Given that,

Time = 1.95 s

Distance = 23.5 m

(a). We need to calculate the velocity

Using equation of motion

Put  the value into the formula

(b). We need to calculate the total distance the object travels during the fall

Using equation of motion

Put the value in the equation

The total time is

We need to calculate the distance

Using equation of motion

Put the value into the formula

Hence, (a). The velocity of the object is -2.496 m/s.

(b).  The total distance of the object travels during the fall is 23.80 m.

answer: good job it's all correct !

explanation:

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