Afreight train has a mass of 1.5 x 10^7 kg. if the
locomotivecan exert a constant pull of 7.5 x1^5 n, how long does it
take toincrease the speed of the train from rest to 80 km/h?

t=444.4s

Explanation:

m=1.5*10^7 kg

F=7.5*10^5 N

v=80km/h*(1h/3600s)*(1000m/1km)=22.22m/s

Second Newton's Law:

F=ma

a=F/m=7.5*10^5/(1.5*10^7)=0.05m/s^2

Kinematics equation:

vf=vo+at=at      

vo: initial velocity equal zero

t=vf/a=22.22/0.05=444.4s

answer: the direction of the wind is expressed as the direction from which the wind is blowing. for example, easterly winds blow from east to west, while westerly winds blow from west to east.

explanation:

its a 5.5 n

glad that