What is the repulsive force between two pith balls that are 11.0 cm apart and have equal charges of −38.0 nc?

Explanation:

Given that,

Charge on two balls,

Distance between charges, r = 11 cm = 0.11 m

We need to find the repulsive force between balls. Mathematically, it is given by :

F = 0.001074 N

or

So, the magnitude of repulsive force between the balls is .

no simpler subs form complex ones. synthesise = make

volts times amps 6 x 0.5 3w