An object is originally moving at a constant velocity of 8 m/s in the -x direction. it moves at this constant velocity for 3 seconds. then, a constant acceleration of 7 m/s2 is applied to it in the +x direction for 9 seconds. what is the total distance covered by this object in meters? give a detailed explanation.

244.64m

Explanation:

First, we find the distance traveled with constant velocity. It's simply multiplying velocity time the time that elapsed:

After this, the ball will start traveling with a constant acceleration motion. Due to the fact that the acceleration is the opposite direction to the initial velocity, this motion will have 2 phases:

1. The velocity will start to decrease untill it reaches 0m/s.

2. Then, the velocity will start to increase at the rate of the acceleration.

The distance that the ball travels in the first phase can be found with the following expression:

Where v is the final velocity (0m/s), v_0 is the initial velocity (-8m/s) and a is the acceleration (+9m/s^2). We solve for d:

Now, before finding the distance traveled in the second phase, we need to find the time that took for the velocity to reach 0:

Then, the time of the second phase will be:

Using this, we using the equations for constant acceleration motion in order to calculate the distance traveled in the second phase:

V_0, the initial velocity of the second phase, will be 0 as previously mentioned. X_0, the initial position, will be 0, for simplicity:

So, the total distance covered by this object in meters will be the sum of all the distances we found:

no. bullets are macro objects. wave nature is for light waves, extremely tiny particles. if a light particle was the size of your finger, the bullet would be the size of the universe. so basically, that huge difference in size makes the wave nature of matter insignificant.