An electric field of intensity 3.0kn is applied along the x axis. calculate the electric flux through a rectangular plane 0.350m wide and 0.700 m long if the following conditions are true: a) the plane is parallel to the yz plane b) the plane is parallel to thte xy plane c) the plane contains the y axis and its normal makes an angle of 30 degrees with the x axis.

Explanation:

Area of plane = .35 x .7 = 0.245 m²

a) When plane is perpendicular to field ( plane is parallel to yz plane. )

Flux = field x area

3000 x .245 = 735 weber

b ) When plane is parallel to xy plane , the plane also becomes parallel to electric field so no flux will pass though the given plane.

Flux through the plane = 0

c ) Since normal to the plane makes 30 degree with x axis, it will also make 30 degree with direction of the field.

Flux through the plane

= electric field x area x cos 30

3000 x .245 x .866

636.51 weber.

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