Arigid adiabatic container is divided into two parts containing n1 and n2 mole of ideal gases respectively, by a movable and thermally conducting wall. their pressure and volume are p1, v1 for part 1 and p2, v2 for part 2 respectively. find the final pressure p and temperature t after the two gas reaches equilibrium. assume the constant volume specific heats of the two gas are the same.

Explanation:

Given

Pressure, Temperature, Volume of gases is

Let P & T be the final Pressure and Temperature

as it is rigid adiabatic container  therefore Q=0 as heat loss by one gas is equal to heat gain by another gas

where Q=heat loss or gain (- heat loss,+heat gain)

W=work done by gas

change in internal Energy of gas

Thus from 1 & 2 we can say that

where

and

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2