An arrow is shot straight up in the air with an initial speed of 250 ft/s. if on striking the ground, it embeds itself 4.00 in into the ground, find the magnitude of the acceleration (assumed constant) required to stop the arrow in units of ft/sec^2

93750 ft/s²

Explanation:

t = Time taken

u = Initial velocity = 250 ft/s (It is assumed that it is speed of the arrow just when it enter the ground)

v = Final velocity = 0

s = Displacement = 4 in =

a = Acceleration

Equation of motion

The magnitude of acceleration is 93750 ft/s²

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