Astone is thrown vertically upward with a speed of 15.0 m/s from the edge of a cliff 75.0 m high. how much later does it reach the bottom of the cliff? what is its speed just before hitting? what total distance did it travel?

5.72 seconds

848.27 m/s

97.94 m

Explanation:

t = Time taken

u = Initial velocity = 15 m/s

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s²

Time taken to reach maximum height is 0.97 seconds

So, the stone would travel 11.47 m up

So, total height stone would fall is 75+11.47 = 86.47 m

Total distance travelled by the stone would be 75+11.47+11.47 = 97.94 m

Time taken by the stone to travel 86.47 m to the water is is 4.2 seconds

The stone reaches the water after 4.2+1.52 = 5.72 seconds after throwing the stone

Speed just before hitting the water is 848.27 m/s

a straight line sloped