A133.7 ft3 volume of liquid hydrogen rocket fuel has a mass of 268 kg. calculate: the weight of the fuel at standard (earth) sea level conditions in n and ibr, the density of the fuel in kg/m3, and the specific volume in ft3/lbm (ibm=pound-mass, which is not the same as a a lbf or a slug)

First, let's make some convertions:

a) weight of the fuel:

Newtons: The weight in newtons is equal to the mass in kilograms times the gravity in m/s^2.

lbf: The weight inlbf is equal to the mass in slugs times the gravity in ft/s^2.

b) density:

The density is the mass in kg of the fuel divided by its volume in m^3:

c) specific volume:

The specific volume is the volume in ft^3 of the fuel divided by its mass in lbm:

an obstruction

i think they are all correct

explanation:

they seem good