An air bubble at the bottom of a lake 36.0 m deep has a volume of 1.22 cm^3. if the temperature at the bottom is 5.9°c and at the top 16.0°c, what is the volume of the bubble just before it reaches the surface?

volume of the bubble just before it reaches the surface is 5.71 cm³

Explanation:

given data

depth h = 36 m

volume v2 = 1.22 cm³ = 1.22 × m³

temperature bottom t2 = 5.9°C = 278.9 K

temperature top  t1 = 16.0°C = 289 K

to find out

what is the volume of the bubble just before it reaches the surface

solution

we know at top atmospheric pressure is about P1 = Pa

so pressure at bottom P2 = pressure at top + ρ×g×h

here ρ is density and h is height and g is 9.8 m/s²

so

pressure at bottom P2 = + 1000 × 9.8 ×36

pressure at bottom P2 =4.52 ×  Pa

so from gas law

here p is pressure and v is volume and t is temperature

so put here value and find v1

V1 = 5.71 cm³

volume of the bubble just before it reaches the surface is 5.71 cm³

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.