What is the magnitude of the electric field at a point midway between a −5.6μc and a +5.8μc charge 9.0cm apart? assume no other charges are nearby. express your answer using two significant figures.

Magnitude of electric field at mid way is

Solution:

As per the question:

Q =

Q' =

Separation distance, d = 9.0 cm = 0.09 m

The distance between charges at mid-way, O is

Now, the electric at point O due to charge Q is:

Here, negative sign is indicative of the direction of electric field which is towards the point O

Now, the electric at point O due to charge Q' is:

Refer to Fig 1.

Since, both the fields are in the same direction:

given data:

determine the horse power (h.p) = ?

force applied to move the box(f) = 10 pounds,

box lifted from a distance         (d) = 3 feet

time taken to lift                         (t) = 10 sec,

the horse power is defined as amount of work required to move a load. the horse power is equal to 550 foot-pound per second

                  1 h.p   = 550 foot-pound/second

it can also be defined as the the load that need to be move a body for certain distance in a certain amount of time.

mathematically,

                      h.p = (force × distance)/ time

                            = (10 × 3)/ 10

                            = 30/10

                            = 3 foot -pound/sec

hence, the horse power is needed to move the box is 3 foot-pound/second

important note: 1 h.p = 550 foot-pound/second = 746 watts

the earths atmosphere is made up of nitrogen and oxygen. solids can turn into gasses through a process called sublimation. sublimation is the transition of a substance directly from the solid to the gas phase, without passing through the intermediate liquid phase.

hope this : d