(a) the energy of photon incident on a material is 1.42 ev. ( determine the minimum frequency of an incident photon that can interact with a valence electron and elevate the electron to become free. (ii) what is the corresponding wavelength? (b) repeat part (a) for a photon energy of 1.12 ev.

a)

3.43*10^{14} Hz

8.75*10^{-7} m

b)

2.70*10^{14} Hz

1.10*10^{-6} m

Explanation:

GIVEN DATA:

a)

i)we know that

E = h\nu

where E is energy

h = plank's constant = 6.625* 10^{-34} j-s

ii)wavelength  is given as

b) i) i)we know that

where E is energy

h = plank's constant = 6.625* 10^{-34} j-s

ii)wavelength  is given as

its c its is a mixture of gases

a

explanation:

no diagram was provided, but i'm guessing it's the one i've attached to my answer.

here, a mechanical force turns the rod.   this generates an electric current in the coil, which powers the bulb.