Atruck covers 47.0 m in 8.60 s while smoothly slowing down to final speed of 2.30 m/s. (a) find its original speed.

Explanation:

Given that,

Distance, s = 47 m

Time taken, t = 8.6 s

Final speed of the truck, v = 2.3 m/s

Let u is the initial speed of the truck and a is its acceleration such that :

.............(1)

Now, the second equation of motion is :

Put the value of a in above equation as :

u = 8.63 m/s

So, the original speed of the truck is 8.63 m/s. Hence, this is the required solution.

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