Abullet fired straight through a board  0.10  m  thick strikes the board with a speed of  480  m/s  and emerges with a speed of  310  m  .
part a
what is the  x  component of the average acceleration of the bullet while in the board? the positive  x  direction is the initial direction of motion of the bullet.
express your answer with the appropriate units.

Explanation:

givens

vf = 310 m/s

vi = 480 m/s

d = 0.1 m

formula

vf^2 = vi^2 + 2*a*d

Solution

310^2 (m/s)^2 = 480^2 (m/s)^2 + 2 * a * 0.1 meters

96100  = 230400  + 2*a * 0.1

96100 - 230400 = 2*a*0.1

-134300 = 2*0.1*a

-134300 = 0.2 *a

-134300/0.2 = a

a = -671500 m/s^2

The important thing to notice is that the acceleration is minus which means the bullet is slowing down.

the temperature in kelvin of 2.0 dm3 of an ideal gas is doubled and its pressure is increased by a factor of four. what is the final volume of the gas