Aball is dropped from the top of a building. after 2 seconds, it’s velocity is measured to be 19.6 m/s. calculate the acceleration for the dropped ball.

Explanation:

The given data is as follows.

        Initial velocity; u = 0,        Final velocity; v = 19.6 m/s

        time; t = 2 seconds

As the relation between initial velocity, final velocity and acceleration is as follows.

                         v = u + at

Hence, putting the given values into the above formula as follows.

                       v = u + at

           19.6 m/s = 0 +

                   a = 9.8              

Thus, we can conclude that acceleration of the dropped ball is 9.8 .

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