Adog walking to the right at  1.5\,\dfrac{\text m}{\text s}1.5sm1, point, 5, space, start fraction, m, divided by, s, end fraction  spies a cat ahead, and begins chasing the cat with a constant acceleration of  12\,\dfrac{\text m}{\text s^2}12s2m12, space, start fraction, m, divided by, s, start superscript, 2, end superscript, end fraction.
what is the velocity of the dog after running for  3.0\,\text m3.0m3, point, 0, space, m?

8.6 m/s

Explanation:

We can find the final velocity of the dog by using the following SUVAT equation:

where

u is the initial velocity

a is the acceleration

d is the distance covered

For the dog in the problem, we have

u = 1.5 m/s

And the distance covered is

d = 3.0 m

Therefore, we can re-arrange the equation to find the final velocity, v:

i am pretty sure it is c because when people are closer together, they cannot move as freely. picture being in a mostly full elevator, for instance. the people are right next to you, and you can barely move.