(1 point) a gun has a muzzle speed of 90 meters per second. what angle of elevation θ, where 0≤θ≤π4, should be used to hit an object 200 meters away? neglect air resistance and use g=9.8m/sec2 as the acceleration of gravit

0.122 radians

Explanation:

Given that the muzzle speed is,

And the distance of the object is,

And acceleration due to gravity is

Therefore negative acceleration due to gravity for upward motion.

Now,

The x component of velocity will be,

The y component of velocity will be,

And the horizontal displacement is given. Now horizontal displacement is,

Here, is horizontal velocity and t is time.

Substitute all the values in above equation, we get

Now, in y direction we can calculate displacement and in y direction displacement is zero.

Substitute all the variables.

Therefore the required angle of elevation is 0.122 radians.

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

according to question, we have said that if the population has twice its initial population, then it becomes

so, time taken to reach this above mentioned population is given by

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.

if they have a finite resultant