During a biopsy of the prostate, a thin needle is used to remove a series of cylindrical tissue samples. if the cylinders have a total length of 28.0 mm and a diameter of 0.100 mm, what is the total mass (in grams) of tissue taken?

9.209×10^{-5} gm.

Explanation:

Given: Length of the cylinder l= 28.0 mm

diameter of the cylinder d= 0.100 mm = radius r = 0.05 mm

The volume of the cylinder is given by V=

also, the density of the prostate generally is 419.3 kg/m^3

which is equal to = 0.4193 g/cm^3

mass= volume×density

mass= 0.4193×pi×r^2×l

mass=

= 9.209×10^{-5} gm.

the total mass of the tissue in grams =  9.209×10^{-5} gm.

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the temperature in kelvin of 2.0 dm3 of an ideal gas is doubled and its pressure is increased by a factor of four. what is the final volume of the gas