Determine the horizontal position x of the cart at t=9.0 s if the cart is located at x =2 m at t = 0

Horizontal position X is 1.1 m

Given:

Initial time t = 0 sec

Final time T = 9 sec

Initial velocity u = 0.8 m/s

Final velocity v = -1 m/s

Initial position X₀ = 2 m

Find:

Horizontal position X

Computation:

We know that;

a = (v - u) / Δt

So,

a = (-1 - 0.8) / (9 - 0)

a = -1.8 / 9

a = -0.2 m/s²

The equation for position X

X = ut + (1/2)(a)(t²) + X₀

X = (0.8)(9) + (1/2)(-0.2)(9²) + 2

X = 7.2 + (-0.1)(81) + 2

X = 9.2 - 8.1

X = 1.1 m

Horizontal position X = 1.1 m

Learn more:

link

1.1m

Explanation:

Given values: time t = 9s, initial position x₀ = 2m, Values from the graph:

initial velocity v₀= 0.8m/s, constant acceleration a = -0.2m/s²(slope of the graph between time t = 0 and t = 9s)

The equation for position x and a constant acceleration is given by:

Using the given values to solve for x:

terd muffin is the correct answer

3.2x10^7