Abasketball shooting guard shoots a free-throw with initial velocity v0 = 3.5 m/s at an angle θ = 22° above the horizontal. use a cartesian coordinate system with the origin located at the position the ball was released, with the ball’s horizontal velocity in the positive x direction and vertical component in the positive y-direction. assume the basketball encounters no air resistance.

3.425 m/s, 1.311 m/s

Explanation:

v0 = 3.5 m/s

θ = 22°

As teh velocity is a vector quantity, so there are two components of velocity.

horizontal component is given by

vx = vo Cos θ = 3.5 x cos 22 = 3.245 m/s

vertical component is given by

vy = vo Sin θ = 3.5 x Sin 22 = 1.311 m/s

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