Two children weighing 15 and 25 kilograms are sitting on opposite sides of a seesaw, both 2 meters from the axis of rotation. where on the seesaw should a 10-kilogram child sit in order to achieve equilibrium? wo children weighing 15 and 25 kilograms are sitting on opposite sides of a seesaw, both 2 meters from the axis of rotation. where on the seesaw should a 10-kilogram child sit in order to achieve equilibrium?

2 m

Explanation:

Let the child of mass 10 kg sits at a distance of d from axis on the side where the 15 kg child is sitting.

According to the principle of moments

Counter clockwise moments about O = clockwise moments about O

15 x g x 2 + 10 x d x g = 25 x g x 2

30 + 10 d = 50

d = 2 m

Thus, the 10 kg child should sit together with 15 kg at a distance of 2 m from the axis so that teh equilibrium is maintained.

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2