We know that the magnitudes of the negative charge on the electron and the positive charge on the proton are equal. suppose, however, that these magnitudes differ from each other by 0.00040%. with what force would two copper coins, placed 1.1 m apart, repel each other? assume that each coin contains 2.5 × 1022 copper atoms. (hint: a neutral copper atom contains 29 protons and 29 electrons.)

Answer: 1.4 seconds which is the third optionexplanation: current is defined as the flow of charge per timetherefore, the equation that relates current, charge and time can be expressed as follows: i = δq / δtwhere: i is the current given = 1.8 ampereδq is the charge given = 2.5 coulombδt is the time required for the flow of the given charges to give the 1.8 ampere.substitute with the givens in the above equation to get the time as follows: 1.8 = 2.5 / δtδt = 2.5 / 1.8 = 1.38888 which is approximately 1.4 secondshope this was !