Abaseball player friend of yours wants to determine his pitching speed. you have him stand on a ledge and throw the ball horizontally from an elevation 4.0 m above the ground. the ball lands 30 m away.

The pitching speed of your friend is 33.20 m/s

Explanation:

Lets explain how to solve the problem

Your friend throw the ball horizontally that means the vertical initial

component of velocity is zero ().

The ball is thrown from a height 4 meters above the ground.

The height

Remember: the height is negative value because its below the point of

thrown (initial position)

h = -4 m , and g = -9.8 m/s²(downward)

Substitute these values in the rule above

⇒

⇒ -4 = -4.9t² (multiply both sides by -1)

⇒ 4 = 4.9t² (divide both sides by 4.9)

⇒ 0.81633 = t² (take √ for both sides)

⇒ t = 0.9035

Then the time of the ball to land on the ground is 0.9035 seconds

The range of the ball on the ground is 30 m

The range , where is the horizontal

component of the initial velocity

R = 30 meters and t = 0.9035

⇒ (divide both sides by 0.9035)

⇒ m/s

The pitching speed of your friend is 33.20 m/s

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2

2b2t

explanation:

2b2t