Two identical asteroids travel side by side while touching one another. if the asteroids are composed of homogeneous pure iron and are spherical, what diameter in feet must they have for their mutual gravitational attraction to be 1 lb?

diameter = 21.81 ft

Explanation:

The gravitational force equation is:

Where:

We also know that the asteroids are identical so their masses are identical:

Since R is the distance between centers of the two asteroids and their diameters are identical (see attachment), we can conclude that:

We don´t know the mass of the asteroids but we know they are composed of pure iron, so we can relate their masses to their density:

This is going to be helpful because the volume of a sphere is:

And know we can write our original force of gravity equation in terms of the radius of the asteroids:

Now let´s plug in the values we know:

Solve for r and multiply by 2 because 2r = diameter

Result is d = 21.81 Feet

answer: i'm not sure which is which for i get confused on it all the time but i can tell you that the answer lies with the convex and concave devices. i hope this you. have a good day and best of luck to you!

explanation: