The velocity of the wind relative to the water is crucial to sailboats. suppose a sailboat is in an ocean current that has a velocity of 2.20 m/s in a direction 30.0º east of north relative to the earth. it encounters a wind that has a velocity of 4.50 m/s in a direction of 50.0º south of west relative to the earth. what is the velocity of the wind relative to the water?

Explanation:

We shall write the velocities given in vector form to make the solution easy.

The velocity of water with respect to earth that is waV(e) makes 30 degree with north or 60 degree with east so in vector form

waV(e) = 2.2 cos 60 i + 2.2 sin 60 j

waV(e) = 1.1 i + 1.9 j

Similarly , velocity of wind with respect to earth that is wiV(e) , is making 50 degree with west or - ve of x axes so we cal write it in vector form as follows

wiV(e) =  - 4.5 cos 50 i - 4.5 sin 50 j

wiV(e) = - 2.89 i - 3.45 j

Now we have to calculate velocity of wind with respect to water that is

wiVwa

wiV( wa) = wiV ( e)+ eV(wa)

=  wiV( e)- waV(e)

- 2.89 i - 3.45 j - 1.1 i -  1.9 j

= - 3.99 i - 5.35 j

Magnitude of this relative velocity

D² = 3.99² + 5.35²

d = 6.67 m /s

the current is 0.6

voltage ÷ resistance = current

so 12 ÷ 20 = 0.6

where are the vectors ?