To take off from the ground, an airplane must reach a sufficiently high speed. the velocity required for the takeoff, the takeoff velocity, depends on several factors, including the weight of the aircraft and the wind velocity.
part a plane accelerates from rest at a constant rate of 5.00m/s2 along a runway that is 1800m long. assume that the plane reaches the required takeoff velocity at the end of the runway. what is the time tto needed to take off?
part c what is the distance dfirst traveled by the plane in the first second of its run?
part d what is the distance dlast traveled by the plane in the last second before taking off?

A) 26.84 s

First of all, we can find the velocity at which the plane takes off, using the equation

where

v is the take-off velocity

u = 0 is the initial velocity

is the acceleration

d = 1800 m is the distance covered

Solving for v,

The time needed to reach this velocity can be found by using

And solving for t,

C) 2.5 m

The distance travelled by the plane in the first second of its run can be found by using

where

u = 0

is the time interval

is the acceleration

Substituting,

D) 131.7 m

To solve this part, we need first to find the velocity of the plane one second before taking off, which is at

The velocity can be found as follows:

Now we can find the distance travelled by the plane during the last second by using

where

v = 129.2 m/s

is the acceleration

Substituting,

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explanation:

v=uf/(u-f)

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