Auniform disk (i =½ mr2 ) of mass 8.0 kg can rotate without friction on a fixed axis. a string is wrapped around its circumference and is attached to a 6.0 kg mass. the string does not slip. what is the tension in the cord while the mass is falling?

T = 23.54 N

Explanation:

Given,

Let 'T' be the tension in the string and 'a' be the acceleration of the block,

Hence, the angular acceleration of the pulley =

From the f.b.d. of the mass

From the f.b.d. of the pulley,

From the eqn (1) and (2), we get,

Hence, the tension in the cord while the mass is falling is 23.54 N

newton's first law of motion

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