The captain of a plane wishes to proceed due west. the cruising speed of the plane is 256 m/s relative to the air. a weather report indicates that a 44.3-m/s wind is blowing from the south to the north. in what direction, measured with respect to due west, should the pilot head the plane?

Angle = 9.965° South of West.

In the question,

The speed of the Plane w.r.t to Wind = 256 m/s

Speed of the Wind w.r.t to Ground = 44.3 m/s

Direction of Wind = North from South

Direction Plane wishes to go = West

So,

Using the vectors,

Speed of Wind w.r.t Ground is given by,

Resultant speed of Plane w.r.t Ground is given by,

So,

From the Vector's Triangle Sum property,

Therefore, the plane has to move in the direction of 'III quadrant' or 'South-West' direction.

Now,

In the triangle, using Pythagoras Theorem,

The speed of the plane = 252.13 m/s

Now,

Therefore, the angle at which the plane should fly to go West is = 9.965° South of West.

muscle endurance

explanation:

i can do 50 in a row ( but i get so tired after that)

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.