Aspeed ramp at an airport is basically a large conveyor belt on which you can stand and be moved along. the belt of one ramp moves at a constant speed such that a person who stands still on it leaves the ramp 64 s after getting on. clifford is in a real hurry, however, and skips the speed ramp. starting from rest with an acceleration of 0.37 m/s2 , he covers the same distance as the ramp does, but in one-fourth the time. what is the speed at which the belt of the ramp is moving?

The belt ramp is moving at 0.047 m/s

Explanation:

Hi!

The equation for the position of an object moving in a straight line with a constant acceleration is:

x = x0 + v0 * t + 1/2 * a * t²

where:

x = position at time "t"

x0 = initial position

v0 = initial velocity

t = time

a = acceleration

If the object moves with constant speed, then, a = 0 and x = x0 + v * t

First, let´s find the lenght of the speed ramp by calculating the distance walked by Clifford.

x = x0 + v0 * t +1/2 * a * t²

x0 = 0 placing the origin of our reference system at the begining of the ramp

v0 = 0 Clifford starts from rest

t = 64 s / 4  

a = 0.37 m/s²

Then:

x = 1/2 * 0.37 m/s² * 16 s = 3.0 m

Now that we know the lenght of the speed ramp, we can calculate the speed of the ramp which is constant:

x = x0 + v * t        x0 = 0

x = v * t

x/t = v

3.0 m / 64 s = 0.047 m/s

answer: cesare beccaria developed the classical school of criminology with from philosopher jeremy bentham

explanation:

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees.