At approximately what altitude above the surface would be pilot expect the base of cumuliform clouds if the surface air temperature is 82f and the dew point is 38f:
a) 8,000 feet agl
b) 9,000 feet agl
c) 10,000 feet agl
d) 11,000 feet agl

10,000 feet AGL

Explanation:

Hi so we have that the difference of temperature is 82°F – 38°F = 44°F

Now we have that  temperature/dew point spread

So replacing the data we obtain 44°F/4.4°F = approximately 10,000 ft. AGL.

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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cant without the picture! ?