The height of a helicopter above the ground is given by h = 3.25t3, where h is in meters and t is in seconds. at t = 2.25 s, the helicopter releases a small mailbag. how long after its release does the mailbag reach the ground?
s

In 2.748 sec the mailbag reached the ground

Explanation:

We have given height from the ground

At t =2.25 sec helicopter releases a small mailbag so at t = 2.25 sec height from the ground

When the mail box is drooped its initial velocity would zero so u = 0 m/sec

Acceleration due to gravity

According to third law of motion

t = 2.748 sec

the closer the planet is to the sun, the larger the gravity

answera compound;